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1003056331391 is a prime number
BaseRepresentation
bin11101001100010101101…
…00001111101001111111
310112220001201110010221222
432212022310033221333
5112413224410101031
62044444150143555
7132316446066122
oct16461264175177
93486051403858
101003056331391
11357437170a04
12142495651bbb
137378454425a
14367963143b9
151b159c35e7b
hexe98ad0fa7f

1003056331391 has 2 divisors, whose sum is σ = 1003056331392. Its totient is φ = 1003056331390.

The previous prime is 1003056331351. The next prime is 1003056331393. The reversal of 1003056331391 is 1931336503001.

It is a strong prime.

It is an emirp because it is prime and its reverse (1931336503001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1003056331391 - 26 = 1003056331327 is a prime.

It is a super-2 number, since 2×10030563313912 (a number of 25 digits) contains 22 as substring.

It is a Sophie Germain prime.

Together with 1003056331393, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1003056331393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501528165695 + 501528165696.

It is an arithmetic number, because the mean of its divisors is an integer number (501528165696).

Almost surely, 21003056331391 is an apocalyptic number.

1003056331391 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003056331391 is an equidigital number, since it uses as much as digits as its factorization.

1003056331391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21870, while the sum is 35.

The spelling of 1003056331391 in words is "one trillion, three billion, fifty-six million, three hundred thirty-one thousand, three hundred ninety-one".