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100311221300 = 22524325192941
BaseRepresentation
bin101110101101100000…
…0111100010000110100
3100120220212021000121112
41131123000330100310
53120414133040200
6114025441334152
710150543212143
oct1353300742064
9316825230545
10100311221300
11395a6084294
1217536037358
1395c8138c64
144bd851575a
152921713535
hex175b03c434

100311221300 has 72 divisors (see below), whose sum is σ = 223627374432. Its totient is φ = 39034800000.

The previous prime is 100311221267. The next prime is 100311221323. The reversal of 100311221300 is 3122113001.

100311221300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1003112213002 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1032830 + ... + 1125770.

It is an arithmetic number, because the mean of its divisors is an integer number (3105935756).

Almost surely, 2100311221300 is an apocalyptic number.

100311221300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100311221300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (111813687216).

100311221300 is an abundant number, since it is smaller than the sum of its proper divisors (123316153132).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100311221300 is a wasteful number, since it uses less digits than its factorization.

100311221300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93249 (or 93242 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 100311221300 its reverse (3122113001), we get a palindrome (103433334301).

The spelling of 100311221300 in words is "one hundred billion, three hundred eleven million, two hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 43 50 86 100 172 215 251 430 502 860 1004 1075 1255 2150 2510 4300 5020 6275 10793 12550 21586 25100 43172 53965 92941 107930 185882 215860 269825 371764 464705 539650 929410 1079300 1858820 2323525 3996463 4647050 7992926 9294100 15985852 19982315 23328191 39964630 46656382 79929260 93312764 99911575 116640955 199823150 233281910 399646300 466563820 583204775 1003112213 1166409550 2006224426 2332819100 4012448852 5015561065 10031122130 20062244260 25077805325 50155610650 100311221300