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100313143559 is a prime number
BaseRepresentation
bin101110101101100100…
…0010001100100000111
3100120220222212200110022
41131123020101210013
53120420131043214
6114025550445355
710150565436326
oct1353310214407
9316828780408
10100313143559
11395a7177532
121753680385b
1395c865cba5
144bd88960bd
152921992d8e
hex175b211907

100313143559 has 2 divisors, whose sum is σ = 100313143560. Its totient is φ = 100313143558.

The previous prime is 100313143547. The next prime is 100313143561. The reversal of 100313143559 is 955341313001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100313143559 - 212 = 100313139463 is a prime.

Together with 100313143561, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100313143519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50156571779 + 50156571780.

It is an arithmetic number, because the mean of its divisors is an integer number (50156571780).

Almost surely, 2100313143559 is an apocalyptic number.

100313143559 is a deficient number, since it is larger than the sum of its proper divisors (1).

100313143559 is an equidigital number, since it uses as much as digits as its factorization.

100313143559 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24300, while the sum is 35.

The spelling of 100313143559 in words is "one hundred billion, three hundred thirteen million, one hundred forty-three thousand, five hundred fifty-nine".