Base | Representation |
---|---|
bin | 11101001100100000000… |
… | …10101011111010000111 |
3 | 10112220021211102100002021 |
4 | 32212100002223322013 |
5 | 112413414331100312 |
6 | 2044501001224011 |
7 | 132321562224103 |
oct | 16462002537207 |
9 | 3486254370067 |
10 | 1003144003207 |
11 | 357481702055 |
12 | 1424baa92007 |
13 | 7379975c578 |
14 | 367a3c16903 |
15 | 1b1627a2c07 |
hex | e9900abe87 |
1003144003207 has 2 divisors, whose sum is σ = 1003144003208. Its totient is φ = 1003144003206.
The previous prime is 1003144003189. The next prime is 1003144003223. The reversal of 1003144003207 is 7023004413001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1003144003207 - 223 = 1003135614599 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1003144003007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501572001603 + 501572001604.
It is an arithmetic number, because the mean of its divisors is an integer number (501572001604).
Almost surely, 21003144003207 is an apocalyptic number.
1003144003207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1003144003207 is an equidigital number, since it uses as much as digits as its factorization.
1003144003207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 1003144003207 its reverse (7023004413001), we get a palindrome (8026148416208).
The spelling of 1003144003207 in words is "one trillion, three billion, one hundred forty-four million, three thousand, two hundred seven".
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