1003333114213 has 2 divisors, whose sum is σ = 1003333114214. Its totient is φ = 1003333114212.

The previous prime is 1003333114183. The next prime is 1003333114237. The reversal of 1003333114213 is 3124113333001.

1003333114213 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 902258716129 + 101074398084 = 949873^2 + 317922^2 .

It is an emirp because it is prime and its reverse (3124113333001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1003333114213 - 2⁵ = 1003333114181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1003333174213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 501666557106 + 501666557107.

It is an arithmetic number, because the mean of its divisors is an integer number (501666557107).

Almost surely, 2^{1003333114213} is an apocalyptic number.

It is an amenable number.

1003333114213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1003333114213 is an equidigital number, since it uses as much as digits as its factorization.

1003333114213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 1003333114213 its reverse (3124113333001), we get a palindrome (4127446447214).

The spelling of 1003333114213 in words is "one trillion, three billion, three hundred thirty-three million, one hundred fourteen thousand, two hundred thirteen".