Base | Representation |
---|---|
bin | 101110101110011001… |
… | …0101000001010101111 |
3 | 100120222221100010102021 |
4 | 1131130302220022233 |
5 | 3120444300222112 |
6 | 114032424211011 |
7 | 10151354424562 |
oct | 1353462501257 |
9 | 316887303367 |
10 | 100341023407 |
11 | 3961098a029 |
12 | 17544009a67 |
13 | 9601371b41 |
14 | 4bdc4724d9 |
15 | 292414d907 |
hex | 175cca82af |
100341023407 has 2 divisors, whose sum is σ = 100341023408. Its totient is φ = 100341023406.
The previous prime is 100341023401. The next prime is 100341023459. The reversal of 100341023407 is 704320143001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100341023407 - 215 = 100340990639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100341023401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50170511703 + 50170511704.
It is an arithmetic number, because the mean of its divisors is an integer number (50170511704).
Almost surely, 2100341023407 is an apocalyptic number.
100341023407 is a deficient number, since it is larger than the sum of its proper divisors (1).
100341023407 is an equidigital number, since it uses as much as digits as its factorization.
100341023407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 100341023407 its reverse (704320143001), we get a palindrome (804661166408).
The spelling of 100341023407 in words is "one hundred billion, three hundred forty-one million, twenty-three thousand, four hundred seven".
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