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10040430023431 is a prime number
BaseRepresentation
bin1001001000011011100001…
…0000111101001100000111
31022112212002211110020120121
42102012320100331030013
52304000300041222211
633204302044442411
72054253134023603
oct222067020751407
938485084406517
1010040430023431
113221138aa4025
121161a9b849407
1357aa68331c02
14269d60878503
1512629456e271
hex921b843d307

10040430023431 has 2 divisors, whose sum is σ = 10040430023432. Its totient is φ = 10040430023430.

The previous prime is 10040430023399. The next prime is 10040430023479. The reversal of 10040430023431 is 13432003404001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10040430023431 - 25 = 10040430023399 is a prime.

It is a super-2 number, since 2×100404300234312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10040430023396 and 10040430023405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10040430023731) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5020215011715 + 5020215011716.

It is an arithmetic number, because the mean of its divisors is an integer number (5020215011716).

Almost surely, 210040430023431 is an apocalyptic number.

10040430023431 is a deficient number, since it is larger than the sum of its proper divisors (1).

10040430023431 is an equidigital number, since it uses as much as digits as its factorization.

10040430023431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 10040430023431 its reverse (13432003404001), we get a palindrome (23472433427432).

The spelling of 10040430023431 in words is "ten trillion, forty billion, four hundred thirty million, twenty-three thousand, four hundred thirty-one".