Base | Representation |
---|---|
bin | 11101001110010100101… |
… | …01111100110111110001 |
3 | 10112222210222221102110212 |
4 | 32213022111330313301 |
5 | 112422420231210303 |
6 | 2045142022033505 |
7 | 132355040203313 |
oct | 16471225746761 |
9 | 3488728842425 |
10 | 1004122131953 |
11 | 357933847716 |
12 | 142732578895 |
13 | 738c42ac685 |
14 | 36857aad7b3 |
15 | 1b1bd5b3ad8 |
hex | e9ca57cdf1 |
1004122131953 has 2 divisors, whose sum is σ = 1004122131954. Its totient is φ = 1004122131952.
The previous prime is 1004122131877. The next prime is 1004122132009. The reversal of 1004122131953 is 3591312214001.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1003088380849 + 1033751104 = 1001543^2 + 32152^2 .
It is a cyclic number.
It is not a de Polignac number, because 1004122131953 - 222 = 1004117937649 is a prime.
It is a super-2 number, since 2×10041221319532 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1004122130953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502061065976 + 502061065977.
It is an arithmetic number, because the mean of its divisors is an integer number (502061065977).
Almost surely, 21004122131953 is an apocalyptic number.
It is an amenable number.
1004122131953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004122131953 is an equidigital number, since it uses as much as digits as its factorization.
1004122131953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 32.
Adding to 1004122131953 its reverse (3591312214001), we get a palindrome (4595434345954).
The spelling of 1004122131953 in words is "one trillion, four billion, one hundred twenty-two million, one hundred thirty-one thousand, nine hundred fifty-three".
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