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100413132341 is a prime number
BaseRepresentation
bin101110110000100010…
…1101100111000110101
3100121011222000122021112
41131201011230320311
53121121230213331
6114043521524405
710153221353654
oct1354105547065
9317158018245
10100413132341
1139648660595
12175641a3705
13961329b552
144c07c8319b
15292a64432b
hex176116ce35

100413132341 has 2 divisors, whose sum is σ = 100413132342. Its totient is φ = 100413132340.

The previous prime is 100413132293. The next prime is 100413132343. The reversal of 100413132341 is 143231314001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 92869515025 + 7543617316 = 304745^2 + 86854^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100413132341 is a prime.

Together with 100413132343, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100413132343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50206566170 + 50206566171.

It is an arithmetic number, because the mean of its divisors is an integer number (50206566171).

Almost surely, 2100413132341 is an apocalyptic number.

It is an amenable number.

100413132341 is a deficient number, since it is larger than the sum of its proper divisors (1).

100413132341 is an equidigital number, since it uses as much as digits as its factorization.

100413132341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 100413132341 its reverse (143231314001), we get a palindrome (243644446342).

The spelling of 100413132341 in words is "one hundred billion, four hundred thirteen million, one hundred thirty-two thousand, three hundred forty-one".