Base | Representation |
---|---|
bin | 11101001110100000110… |
… | …11000011011111011011 |
3 | 10120000002002212121201111 |
4 | 32213100123003133123 |
5 | 112423122334224313 |
6 | 2045200104201151 |
7 | 132360416201563 |
oct | 16472033033733 |
9 | 3500062777644 |
10 | 1004224133083 |
11 | 357986385676 |
12 | 1427607691b7 |
13 | 7390c473c82 |
14 | 36867461da3 |
15 | 1b1c751143d |
hex | e9d06c37db |
1004224133083 has 2 divisors, whose sum is σ = 1004224133084. Its totient is φ = 1004224133082.
The previous prime is 1004224133027. The next prime is 1004224133111. The reversal of 1004224133083 is 3803314224001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1004224133083 - 221 = 1004222035931 is a prime.
It is a super-2 number, since 2×10042241330832 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1004224133483) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502112066541 + 502112066542.
It is an arithmetic number, because the mean of its divisors is an integer number (502112066542).
Almost surely, 21004224133083 is an apocalyptic number.
1004224133083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004224133083 is an equidigital number, since it uses as much as digits as its factorization.
1004224133083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 1004224133083 its reverse (3803314224001), we get a palindrome (4807538357084).
The spelling of 1004224133083 in words is "one trillion, four billion, two hundred twenty-four million, one hundred thirty-three thousand, eighty-three".
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