Base | Representation |
---|---|
bin | 11101001110100000110… |
… | …11000011011111110111 |
3 | 10120000002002212121202112 |
4 | 32213100123003133313 |
5 | 112423122334224421 |
6 | 2045200104201235 |
7 | 132360416201633 |
oct | 16472033033767 |
9 | 3500062777675 |
10 | 1004224133111 |
11 | 3579863856a1 |
12 | 14276076921b |
13 | 7390c473ca4 |
14 | 36867461dc3 |
15 | 1b1c751145b |
hex | e9d06c37f7 |
1004224133111 has 2 divisors, whose sum is σ = 1004224133112. Its totient is φ = 1004224133110.
The previous prime is 1004224133083. The next prime is 1004224133123. The reversal of 1004224133111 is 1113314224001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1004224133111 - 218 = 1004223870967 is a prime.
It is a super-2 number, since 2×10042241331112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1004224133131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502112066555 + 502112066556.
It is an arithmetic number, because the mean of its divisors is an integer number (502112066556).
Almost surely, 21004224133111 is an apocalyptic number.
1004224133111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1004224133111 is an equidigital number, since it uses as much as digits as its factorization.
1004224133111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 1004224133111 its reverse (1113314224001), we get a palindrome (2117538357112).
The spelling of 1004224133111 in words is "one trillion, four billion, two hundred twenty-four million, one hundred thirty-three thousand, one hundred eleven".
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