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10043141213117 is a prime number
BaseRepresentation
bin1001001000100101100111…
…0111010100101110111101
31022120010002210000221122102
42102021121313110232331
52304021323122304432
633205431054554445
72054410254532655
oct222113167245675
938503083027572
1010043141213117
1132222aa432a61
121162517808a25
1357b0aac3586c
1426a13a981365
151263a25b4962
hex92259dd4bbd

10043141213117 has 2 divisors, whose sum is σ = 10043141213118. Its totient is φ = 10043141213116.

The previous prime is 10043141213057. The next prime is 10043141213143. The reversal of 10043141213117 is 71131214134001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7359658211161 + 2683483001956 = 2712869^2 + 1638134^2 .

It is a cyclic number.

It is not a de Polignac number, because 10043141213117 - 232 = 10038846245821 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10043141213117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10043141213167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021570606558 + 5021570606559.

It is an arithmetic number, because the mean of its divisors is an integer number (5021570606559).

Almost surely, 210043141213117 is an apocalyptic number.

It is an amenable number.

10043141213117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10043141213117 is an equidigital number, since it uses as much as digits as its factorization.

10043141213117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 29.

Adding to 10043141213117 its reverse (71131214134001), we get a palindrome (81174355347118).

The spelling of 10043141213117 in words is "ten trillion, forty-three billion, one hundred forty-one million, two hundred thirteen thousand, one hundred seventeen".