Base | Representation |
---|---|
bin | 10010101101010001… |
… | …00101001100111011 |
3 | 221220221110020222122 |
4 | 21112220211030323 |
5 | 131032103211212 |
6 | 4340333111455 |
7 | 503612414234 |
oct | 112650451473 |
9 | 27827406878 |
10 | 10043413307 |
11 | 4294277084 |
12 | 1b4362858b |
13 | c409aa815 |
14 | 6b3c2408b |
15 | 3dbad6272 |
hex | 256a2533b |
10043413307 has 2 divisors, whose sum is σ = 10043413308. Its totient is φ = 10043413306.
The previous prime is 10043413291. The next prime is 10043413309. The reversal of 10043413307 is 70331434001.
10043413307 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10043413307 - 24 = 10043413291 is a prime.
Together with 10043413309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10043413309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021706653 + 5021706654.
It is an arithmetic number, because the mean of its divisors is an integer number (5021706654).
Almost surely, 210043413307 is an apocalyptic number.
10043413307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10043413307 is an equidigital number, since it uses as much as digits as its factorization.
10043413307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 26.
Adding to 10043413307 its reverse (70331434001), we get a palindrome (80374847308).
The spelling of 10043413307 in words is "ten billion, forty-three million, four hundred thirteen thousand, three hundred seven".
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