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10043413309 is a prime number
BaseRepresentation
bin10010101101010001…
…00101001100111101
3221220221110020222201
421112220211030331
5131032103211214
64340333111501
7503612414236
oct112650451475
927827406881
1010043413309
114294277086
121b43628591
13c409aa817
146b3c2408d
153dbad6274
hex256a2533d

10043413309 has 2 divisors, whose sum is σ = 10043413310. Its totient is φ = 10043413308.

The previous prime is 10043413307. The next prime is 10043413327. The reversal of 10043413309 is 90331434001.

10043413309 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5059476900 + 4983936409 = 71130^2 + 70597^2 .

It is a cyclic number.

It is not a de Polignac number, because 10043413309 - 21 = 10043413307 is a prime.

Together with 10043413307, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10043413307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5021706654 + 5021706655.

It is an arithmetic number, because the mean of its divisors is an integer number (5021706655).

Almost surely, 210043413309 is an apocalyptic number.

It is an amenable number.

10043413309 is a deficient number, since it is larger than the sum of its proper divisors (1).

10043413309 is an equidigital number, since it uses as much as digits as its factorization.

10043413309 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 28.

The spelling of 10043413309 in words is "ten billion, forty-three million, four hundred thirteen thousand, three hundred nine".