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100450034505551 is a prime number
BaseRepresentation
bin10110110101101111011000…
…100111111101011101001111
3111011122221002121122010121202
4112311233120213331131033
5101131233132313134201
6553350035300020115
730105163332261263
oct2665573047753517
9434587077563552
10100450034505551
112a00869082a105
12b323a8139163b
134408522715993
141ab3b441280a3
15b92e08ac6c6b
hex5b5bd89fd74f

100450034505551 has 2 divisors, whose sum is σ = 100450034505552. Its totient is φ = 100450034505550.

The previous prime is 100450034505529. The next prime is 100450034505617. The reversal of 100450034505551 is 155505430054001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100450034505551 - 226 = 100449967396687 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100450034505451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50225017252775 + 50225017252776.

It is an arithmetic number, because the mean of its divisors is an integer number (50225017252776).

Almost surely, 2100450034505551 is an apocalyptic number.

100450034505551 is a deficient number, since it is larger than the sum of its proper divisors (1).

100450034505551 is an equidigital number, since it uses as much as digits as its factorization.

100450034505551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 150000, while the sum is 38.

Adding to 100450034505551 its reverse (155505430054001), we get a palindrome (255955464559552).

The spelling of 100450034505551 in words is "one hundred trillion, four hundred fifty billion, thirty-four million, five hundred five thousand, five hundred fifty-one".