Base | Representation |
---|---|
bin | 10110110110100011100001… |
… | …000101101111011101011111 |
3 | 111011212021120201111000120011 |
4 | 112312203201011233131133 |
5 | 101133142302320330434 |
6 | 553431454000504051 |
7 | 30112214435441464 |
oct | 2666434105573537 |
9 | 434767521430504 |
10 | 100506011105119 |
11 | 2a02a3a609a944 |
12 | b3328a391b027 |
13 | 44108a374a349 |
14 | 1ab67344d566b |
15 | b945d2ed0e64 |
hex | 5b68e116f75f |
100506011105119 has 2 divisors, whose sum is σ = 100506011105120. Its totient is φ = 100506011105118.
The previous prime is 100506011105113. The next prime is 100506011105131. The reversal of 100506011105119 is 911501110605001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100506011105119 - 23 = 100506011105111 is a prime.
It is a super-2 number, since 2×1005060111051192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100506011105111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50253005552559 + 50253005552560.
It is an arithmetic number, because the mean of its divisors is an integer number (50253005552560).
Almost surely, 2100506011105119 is an apocalyptic number.
100506011105119 is a deficient number, since it is larger than the sum of its proper divisors (1).
100506011105119 is an equidigital number, since it uses as much as digits as its factorization.
100506011105119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 31.
The spelling of 100506011105119 in words is "one hundred trillion, five hundred six billion, eleven million, one hundred five thousand, one hundred nineteen".
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