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100506011105113 is a prime number
BaseRepresentation
bin10110110110100011100001…
…000101101111011101011001
3111011212021120201111000112221
4112312203201011233131121
5101133142302320330423
6553431454000504041
730112214435441455
oct2666434105573531
9434767521430487
10100506011105113
112a02a3a609a939
12b3328a391b021
1344108a374a343
141ab67344d5665
15b945d2ed0e5d
hex5b68e116f759

100506011105113 has 2 divisors, whose sum is σ = 100506011105114. Its totient is φ = 100506011105112.

The previous prime is 100506011105111. The next prime is 100506011105119. The reversal of 100506011105113 is 311501110605001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99409913084304 + 1096098020809 = 9970452^2 + 1046947^2 .

It is a cyclic number.

It is not a de Polignac number, because 100506011105113 - 21 = 100506011105111 is a prime.

It is a super-2 number, since 2×1005060111051132 (a number of 29 digits) contains 22 as substring.

Together with 100506011105111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (100506011105111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50253005552556 + 50253005552557.

It is an arithmetic number, because the mean of its divisors is an integer number (50253005552557).

Almost surely, 2100506011105113 is an apocalyptic number.

It is an amenable number.

100506011105113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100506011105113 is an equidigital number, since it uses as much as digits as its factorization.

100506011105113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 25.

The spelling of 100506011105113 in words is "one hundred trillion, five hundred six billion, eleven million, one hundred five thousand, one hundred thirteen".