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10052140750 = 25340208563
BaseRepresentation
bin10010101110010011…
…10111111011001110
3221221112212122210021
421113021313323032
5131041322001000
64341244132354
7504046533541
oct112711677316
927845778707
1010052140750
114299198143
121b465370ba
13c427450a2
146b5056858
153dc75c11a
hex257277ece

10052140750 has 16 divisors (see below), whose sum is σ = 18817607952. Its totient is φ = 4020856200.

The previous prime is 10052140729. The next prime is 10052140751. The reversal of 10052140750 is 5704125001.

It is a super-3 number, since 3×100521407503 (a number of 31 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10052140751) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20104032 + ... + 20104531.

It is an arithmetic number, because the mean of its divisors is an integer number (1176100497).

Almost surely, 210052140750 is an apocalyptic number.

10052140750 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

10052140750 is a deficient number, since it is larger than the sum of its proper divisors (8765467202).

10052140750 is an equidigital number, since it uses as much as digits as its factorization.

10052140750 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40208580 (or 40208570 counting only the distinct ones).

The product of its (nonzero) digits is 1400, while the sum is 25.

Adding to 10052140750 its reverse (5704125001), we get a palindrome (15756265751).

The spelling of 10052140750 in words is "ten billion, fifty-two million, one hundred forty thousand, seven hundred fifty".

Divisors: 1 2 5 10 25 50 125 250 40208563 80417126 201042815 402085630 1005214075 2010428150 5026070375 10052140750