Search a number
-
+
1005251301491 is a prime number
BaseRepresentation
bin11101010000011011010…
…01011001000001110011
310120002201200200011212212
432220031221121001303
5112432223313121431
62045450040042335
7132425031035633
oct16501551310163
93502650604785
101005251301491
11358363175488
121429a87633ab
1373a44204328
1436923a426c3
151b2377ac72b
hexea0da59073

1005251301491 has 2 divisors, whose sum is σ = 1005251301492. Its totient is φ = 1005251301490.

The previous prime is 1005251301451. The next prime is 1005251301493. The reversal of 1005251301491 is 1941031525001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1005251301491 - 210 = 1005251300467 is a prime.

It is a super-3 number, since 3×10052513014913 (a number of 37 digits) contains 333 as substring.

Together with 1005251301493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1005251301493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502625650745 + 502625650746.

It is an arithmetic number, because the mean of its divisors is an integer number (502625650746).

Almost surely, 21005251301491 is an apocalyptic number.

1005251301491 is a deficient number, since it is larger than the sum of its proper divisors (1).

1005251301491 is an equidigital number, since it uses as much as digits as its factorization.

1005251301491 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 32.

Adding to 1005251301491 its reverse (1941031525001), we get a palindrome (2946282826492).

The spelling of 1005251301491 in words is "one trillion, five billion, two hundred fifty-one million, three hundred one thousand, four hundred ninety-one".