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100530613034471 is a prime number
BaseRepresentation
bin10110110110111010011011…
…011110101001110111100111
3111011221122002021100112002202
4112312322123132221313213
5101134043143414100341
6553451043121325115
730114045210415154
oct2666723336516747
9434848067315082
10100530613034471
112a039880259564
12b33760aa9679b
134412cc46694a9
141ab79c9a5b22b
15b95072c7179b
hex5b6e9b7a9de7

100530613034471 has 2 divisors, whose sum is σ = 100530613034472. Its totient is φ = 100530613034470.

The previous prime is 100530613034429. The next prime is 100530613034483. The reversal of 100530613034471 is 174430316035001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100530613034471 - 230 = 100529539292647 is a prime.

It is a super-3 number, since 3×1005306130344713 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100530610034471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50265306517235 + 50265306517236.

It is an arithmetic number, because the mean of its divisors is an integer number (50265306517236).

Almost surely, 2100530613034471 is an apocalyptic number.

100530613034471 is a deficient number, since it is larger than the sum of its proper divisors (1).

100530613034471 is an equidigital number, since it uses as much as digits as its factorization.

100530613034471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 38.

Adding to 100530613034471 its reverse (174430316035001), we get a palindrome (274960929069472).

The spelling of 100530613034471 in words is "one hundred trillion, five hundred thirty billion, six hundred thirteen million, thirty-four thousand, four hundred seventy-one".