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100551253131551 is a prime number
BaseRepresentation
bin10110110111001101101001…
…101110011000000100011111
3111012000121100201100002110202
4112313031221232120010133
5101134412431300202201
6553504335154254115
730115405534352255
oct2667155156300437
9435017321302422
10100551253131551
112a047602032a32
12b33b60b28733b
134414c3383b7a1
141ab89c6d665d5
15b9587eccac6b
hex5b7369b9811f

100551253131551 has 2 divisors, whose sum is σ = 100551253131552. Its totient is φ = 100551253131550.

The previous prime is 100551253131533. The next prime is 100551253131583. The reversal of 100551253131551 is 155131352155001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 100551253131551 - 214 = 100551253115167 is a prime.

It is a super-3 number, since 3×1005512531315513 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100551253131751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50275626565775 + 50275626565776.

It is an arithmetic number, because the mean of its divisors is an integer number (50275626565776).

Almost surely, 2100551253131551 is an apocalyptic number.

100551253131551 is a deficient number, since it is larger than the sum of its proper divisors (1).

100551253131551 is an equidigital number, since it uses as much as digits as its factorization.

100551253131551 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56250, while the sum is 38.

The spelling of 100551253131551 in words is "one hundred trillion, five hundred fifty-one billion, two hundred fifty-three million, one hundred thirty-one thousand, five hundred fifty-one".