Base | Representation |
---|---|
bin | 11101010000111011010… |
… | …10100000111010101111 |
3 | 10120010102102100002000201 |
4 | 32220131222200322233 |
5 | 112433301112001112 |
6 | 2045532435534331 |
7 | 132434503150033 |
oct | 16503552407257 |
9 | 3503372302021 |
10 | 1005520031407 |
11 | 358490931221 |
12 | 142a6275a3a7 |
13 | 73a87aa4008 |
14 | 3694b5d61c3 |
15 | 1b251191257 |
hex | ea1daa0eaf |
1005520031407 has 2 divisors, whose sum is σ = 1005520031408. Its totient is φ = 1005520031406.
The previous prime is 1005520031353. The next prime is 1005520031413. The reversal of 1005520031407 is 7041300255001.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1005520031407 - 211 = 1005520029359 is a prime.
It is a super-2 number, since 2×10055200314072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1005520031107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 502760015703 + 502760015704.
It is an arithmetic number, because the mean of its divisors is an integer number (502760015704).
Almost surely, 21005520031407 is an apocalyptic number.
1005520031407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1005520031407 is an equidigital number, since it uses as much as digits as its factorization.
1005520031407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4200, while the sum is 28.
Adding to 1005520031407 its reverse (7041300255001), we get a palindrome (8046820286408).
The spelling of 1005520031407 in words is "one trillion, five billion, five hundred twenty million, thirty-one thousand, four hundred seven".
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