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10077294893 is a prime number
BaseRepresentation
bin10010110001010011…
…10101000100101101
3222000022012121210012
421120221311010231
5131114241414033
64343543223005
7504503410331
oct113051650455
928008177705
1010077294893
114301408896
121b52a47a65
13c47a114b3
146b85237c1
153dea7a248
hex258a7512d

10077294893 has 2 divisors, whose sum is σ = 10077294894. Its totient is φ = 10077294892.

The previous prime is 10077294797. The next prime is 10077294943. The reversal of 10077294893 is 39849277001.

It is an a-pointer prime, because the next prime (10077294943) can be obtained adding 10077294893 to its sum of digits (50).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6763911049 + 3313383844 = 82243^2 + 57562^2 .

It is an emirp because it is prime and its reverse (39849277001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10077294893 - 28 = 10077294637 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10070294893) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5038647446 + 5038647447.

It is an arithmetic number, because the mean of its divisors is an integer number (5038647447).

Almost surely, 210077294893 is an apocalyptic number.

It is an amenable number.

10077294893 is a deficient number, since it is larger than the sum of its proper divisors (1).

10077294893 is an equidigital number, since it uses as much as digits as its factorization.

10077294893 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 762048, while the sum is 50.

The spelling of 10077294893 in words is "ten billion, seventy-seven million, two hundred ninety-four thousand, eight hundred ninety-three".