10083201911 has 2 divisors, whose sum is σ = 10083201912. Its totient is φ = 10083201910.

The previous prime is 10083201901. The next prime is 10083201913. The reversal of 10083201911 is 11910238001.

10083201911 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10083201911 - 2¹⁰ = 10083200887 is a prime.

Together with 10083201913, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10083201913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5041600955 + 5041600956.

It is an arithmetic number, because the mean of its divisors is an integer number (5041600956).

Almost surely, 2^10083201911 is an apocalyptic number.

10083201911 is a deficient number, since it is larger than the sum of its proper divisors (1).

10083201911 is an equidigital number, since it uses as much as digits as its factorization.

10083201911 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 26.

Adding to 10083201911 its reverse (11910238001), we get a palindrome (21993439912).

The spelling of 10083201911 in words is "ten billion, eighty-three million, two hundred one thousand, nine hundred eleven".