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10098121947533 is a prime number
BaseRepresentation
bin1001001011110010011011…
…1110001011100110001101
31022202101000110222122102022
42102330212332023212031
52310421423204310113
633251002502535525
72061364606213214
oct222744676134615
938671013878368
1010098121947533
113243653644544
1211711007375a5
1358333084a0c9
1426ca7499a07b
15127a1e357908
hex92f26f8b98d

10098121947533 has 2 divisors, whose sum is σ = 10098121947534. Its totient is φ = 10098121947532.

The previous prime is 10098121947517. The next prime is 10098121947547. The reversal of 10098121947533 is 33574912189001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5784616645129 + 4313505302404 = 2405123^2 + 2076898^2 .

It is a cyclic number.

It is not a de Polignac number, because 10098121947533 - 24 = 10098121947517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10098121947503) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5049060973766 + 5049060973767.

It is an arithmetic number, because the mean of its divisors is an integer number (5049060973767).

Almost surely, 210098121947533 is an apocalyptic number.

It is an amenable number.

10098121947533 is a deficient number, since it is larger than the sum of its proper divisors (1).

10098121947533 is an equidigital number, since it uses as much as digits as its factorization.

10098121947533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1632960, while the sum is 53.

The spelling of 10098121947533 in words is "ten trillion, ninety-eight billion, one hundred twenty-one million, nine hundred forty-seven thousand, five hundred thirty-three".