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100993841240917 is a prime number
BaseRepresentation
bin10110111101101001110110…
…000010000001101101010101
3111020120220202102221120120111
4112331221312002001231111
5101214140341324202132
6554443532525403021
730162364351252402
oct2675516602015525
9436526672846514
10100993841240917
112a1a827a527229
12b3b1349109471
1344478a849b031
141ad21b13212a9
15ba21354dd647
hex5bda76081b55

100993841240917 has 2 divisors, whose sum is σ = 100993841240918. Its totient is φ = 100993841240916.

The previous prime is 100993841240899. The next prime is 100993841240933. The reversal of 100993841240917 is 719042148399001.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70977019145796 + 30016822095121 = 8424786^2 + 5478761^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100993841240917 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100993841240717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50496920620458 + 50496920620459.

It is an arithmetic number, because the mean of its divisors is an integer number (50496920620459).

Almost surely, 2100993841240917 is an apocalyptic number.

It is an amenable number.

100993841240917 is a deficient number, since it is larger than the sum of its proper divisors (1).

100993841240917 is an equidigital number, since it uses as much as digits as its factorization.

100993841240917 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3919104, while the sum is 58.

The spelling of 100993841240917 in words is "one hundred trillion, nine hundred ninety-three billion, eight hundred forty-one million, two hundred forty thousand, nine hundred seventeen".