Base | Representation |
---|---|
bin | 11101011001010001011… |
… | …00100111011101011111 |
3 | 10120112222122101002122021 |
4 | 32230220230213131133 |
5 | 113021440011133132 |
6 | 2051553155201011 |
7 | 132653513123053 |
oct | 16545054473537 |
9 | 3515878332567 |
10 | 1010000099167 |
11 | 35a37a7a8464 |
12 | 1438b2ba6167 |
13 | 7431ccbc197 |
14 | 36c545d3c63 |
15 | 1b414643997 |
hex | eb28b2775f |
1010000099167 has 2 divisors, whose sum is σ = 1010000099168. Its totient is φ = 1010000099166.
The previous prime is 1010000099153. The next prime is 1010000099179. The reversal of 1010000099167 is 7619900000101.
It is a strong prime.
It is an emirp because it is prime and its reverse (7619900000101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1010000099167 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1010000099137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505000049583 + 505000049584.
It is an arithmetic number, because the mean of its divisors is an integer number (505000049584).
Almost surely, 21010000099167 is an apocalyptic number.
1010000099167 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010000099167 is an equidigital number, since it uses as much as digits as its factorization.
1010000099167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 34.
Adding to 1010000099167 its reverse (7619900000101), we get a palindrome (8629900099268).
The spelling of 1010000099167 in words is "one trillion, ten billion, ninety-nine thousand, one hundred sixty-seven".
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