Base | Representation |
---|---|
bin | 10110111101101111100101… |
… | …101101111101000101101111 |
3 | 111020121111200100112201210101 |
4 | 112331233211231331011233 |
5 | 101214241010024311412 |
6 | 554450433011251531 |
7 | 30163003254636133 |
oct | 2675574555750557 |
9 | 436544610481711 |
10 | 101000009994607 |
11 | 2a1aa955639179 |
12 | b3b258aba9ba7 |
13 | 444834c500a49 |
14 | 1ad25d86db3c3 |
15 | ba2396d5c457 |
hex | 5bdbe5b7d16f |
101000009994607 has 2 divisors, whose sum is σ = 101000009994608. Its totient is φ = 101000009994606.
The previous prime is 101000009994601. The next prime is 101000009994643. The reversal of 101000009994607 is 706499900000101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101000009994607 - 211 = 101000009992559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101000009994601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500004997303 + 50500004997304.
It is an arithmetic number, because the mean of its divisors is an integer number (50500004997304).
Almost surely, 2101000009994607 is an apocalyptic number.
101000009994607 is a deficient number, since it is larger than the sum of its proper divisors (1).
101000009994607 is an equidigital number, since it uses as much as digits as its factorization.
101000009994607 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 46.
Adding to 101000009994607 its reverse (706499900000101), we get a palindrome (807499909994708).
The spelling of 101000009994607 in words is "one hundred one trillion, nine million, nine hundred ninety-four thousand, six hundred seven".
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