Base | Representation |
---|---|
bin | 10110111101101111100101… |
… | …101101111101000110010011 |
3 | 111020121111200100112201211201 |
4 | 112331233211231331012103 |
5 | 101214241010024312033 |
6 | 554450433011252031 |
7 | 30163003254636214 |
oct | 2675574555750623 |
9 | 436544610481751 |
10 | 101000009994643 |
11 | 2a1aa955639201 |
12 | b3b258abaa017 |
13 | 444834c500a76 |
14 | 1ad25d86db40b |
15 | ba2396d5c47d |
hex | 5bdbe5b7d193 |
101000009994643 has 2 divisors, whose sum is σ = 101000009994644. Its totient is φ = 101000009994642.
The previous prime is 101000009994607. The next prime is 101000009994707. The reversal of 101000009994643 is 346499900000101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101000009994643 - 245 = 65815637905811 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101000009994593 and 101000009994602.
It is not a weakly prime, because it can be changed into another prime (101000009994943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500004997321 + 50500004997322.
It is an arithmetic number, because the mean of its divisors is an integer number (50500004997322).
Almost surely, 2101000009994643 is an apocalyptic number.
101000009994643 is a deficient number, since it is larger than the sum of its proper divisors (1).
101000009994643 is an equidigital number, since it uses as much as digits as its factorization.
101000009994643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 209952, while the sum is 46.
Adding to 101000009994643 its reverse (346499900000101), we get a palindrome (447499909994744).
The spelling of 101000009994643 in words is "one hundred one trillion, nine million, nine hundred ninety-four thousand, six hundred forty-three".
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