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101000009994707 is a prime number
BaseRepresentation
bin10110111101101111100101…
…101101111101000111010011
3111020121111200100112201221002
4112331233211231331013103
5101214241010024312312
6554450433011252215
730163003254636335
oct2675574555750723
9436544610481832
10101000009994707
112a1aa95563925a
12b3b258abaa06b
13444834c500ac5
141ad25d86db455
15ba2396d5c4c2
hex5bdbe5b7d1d3

101000009994707 has 2 divisors, whose sum is σ = 101000009994708. Its totient is φ = 101000009994706.

The previous prime is 101000009994643. The next prime is 101000009994727. The reversal of 101000009994707 is 707499900000101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101000009994707 - 26 = 101000009994643 is a prime.

It is a super-3 number, since 3×1010000099947073 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (101000009994727) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500004997353 + 50500004997354.

It is an arithmetic number, because the mean of its divisors is an integer number (50500004997354).

Almost surely, 2101000009994707 is an apocalyptic number.

101000009994707 is a deficient number, since it is larger than the sum of its proper divisors (1).

101000009994707 is an equidigital number, since it uses as much as digits as its factorization.

101000009994707 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 142884, while the sum is 47.

Adding to 101000009994707 its reverse (707499900000101), we get a palindrome (808499909994808).

The spelling of 101000009994707 in words is "one hundred one trillion, nine million, nine hundred ninety-four thousand, seven hundred seven".