Base | Representation |
---|---|
bin | 10110111101101111100101… |
… | …101101111101000111010011 |
3 | 111020121111200100112201221002 |
4 | 112331233211231331013103 |
5 | 101214241010024312312 |
6 | 554450433011252215 |
7 | 30163003254636335 |
oct | 2675574555750723 |
9 | 436544610481832 |
10 | 101000009994707 |
11 | 2a1aa95563925a |
12 | b3b258abaa06b |
13 | 444834c500ac5 |
14 | 1ad25d86db455 |
15 | ba2396d5c4c2 |
hex | 5bdbe5b7d1d3 |
101000009994707 has 2 divisors, whose sum is σ = 101000009994708. Its totient is φ = 101000009994706.
The previous prime is 101000009994643. The next prime is 101000009994727. The reversal of 101000009994707 is 707499900000101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101000009994707 - 26 = 101000009994643 is a prime.
It is a super-3 number, since 3×1010000099947073 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (101000009994727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500004997353 + 50500004997354.
It is an arithmetic number, because the mean of its divisors is an integer number (50500004997354).
Almost surely, 2101000009994707 is an apocalyptic number.
101000009994707 is a deficient number, since it is larger than the sum of its proper divisors (1).
101000009994707 is an equidigital number, since it uses as much as digits as its factorization.
101000009994707 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 142884, while the sum is 47.
Adding to 101000009994707 its reverse (707499900000101), we get a palindrome (808499909994808).
The spelling of 101000009994707 in words is "one hundred one trillion, nine million, nine hundred ninety-four thousand, seven hundred seven".
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