10100011131300 has 72 divisors (see below), whose sum is σ = 29574779655456. Its totient is φ = 2660886460160.

The previous prime is 10100011131277. The next prime is 10100011131337. The reversal of 10100011131300 is 313111000101.

10100011131300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 202786569 + ... + 202836368.

It is an arithmetic number, because the mean of its divisors is an integer number (410760828548).

Almost surely, 2^{10100011131300} is an apocalyptic number.

10100011131300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

10100011131300 is an abundant number, since it is smaller than the sum of its proper divisors (19474768524156).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

10100011131300 is a wasteful number, since it uses less digits than its factorization.

10100011131300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 405623037 (or 405623030 counting only the distinct ones).

The product of its (nonzero) digits is 9, while the sum is 12.

Adding to 10100011131300 its reverse (313111000101), we get a palindrome (10413122131401).

The spelling of 10100011131300 in words is "ten trillion, one hundred billion, eleven million, one hundred thirty-one thousand, three hundred".