Base | Representation |
---|---|
bin | 10110111101110000100111… |
… | …010010001001000111010011 |
3 | 111020121121112000101210121221 |
4 | 112331300213102021013103 |
5 | 101214300233130000313 |
6 | 554451134104225511 |
7 | 30163042442554156 |
oct | 2675604722110723 |
9 | 436547460353557 |
10 | 101001110000083 |
11 | 2a20036a557607 |
12 | b3b283746b297 |
13 | 4448496384067 |
14 | 1ad26a083bc9d |
15 | ba240d6e4c8d |
hex | 5bdc274891d3 |
101001110000083 has 2 divisors, whose sum is σ = 101001110000084. Its totient is φ = 101001110000082.
The previous prime is 101001110000081. The next prime is 101001110000107. The reversal of 101001110000083 is 380000011100101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 101001110000083 - 21 = 101001110000081 is a prime.
Together with 101001110000081, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (101001110000081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50500555000041 + 50500555000042.
It is an arithmetic number, because the mean of its divisors is an integer number (50500555000042).
Almost surely, 2101001110000083 is an apocalyptic number.
101001110000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
101001110000083 is an equidigital number, since it uses as much as digits as its factorization.
101001110000083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 16.
Adding to 101001110000083 its reverse (380000011100101), we get a palindrome (481001121100184).
The spelling of 101001110000083 in words is "one hundred one trillion, one billion, one hundred ten million, eighty-three", and thus it is an aban number.
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