10100313011 has 2 divisors, whose sum is σ = 10100313012. Its totient is φ = 10100313010.

The previous prime is 10100312993. The next prime is 10100313029. The reversal of 10100313011 is 11031300101.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (10100312993) and next prime (10100313029).

It is an emirp because it is prime and its reverse (11031300101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10100313011 - 2¹⁸ = 10100050867 is a prime.

It is a super-2 number, since 2×10100313011² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10100312983 and 10100313001.

It is not a weakly prime, because it can be changed into another prime (10100313061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5050156505 + 5050156506.

It is an arithmetic number, because the mean of its divisors is an integer number (5050156506).

Almost surely, 2^10100313011 is an apocalyptic number.

10100313011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10100313011 is an equidigital number, since it uses as much as digits as its factorization.

10100313011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 10100313011 its reverse (11031300101), we get a palindrome (21131613112).

The spelling of 10100313011 in words is "ten billion, one hundred million, three hundred thirteen thousand, eleven".