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101011100999489 is a prime number
BaseRepresentation
bin10110111101111001111010…
…110010110001111101000001
3111020122120022022020011020222
4112331321322302301331001
5101214431213323440424
6554455505330112425
730163545150631262
oct2675717262617501
9436576268204228
10101011100999489
112a20462718430a
12b3b476541b715
1344493c923c825
141ad2d6b6da969
15ba27e58c5e5e
hex5bde7acb1f41

101011100999489 has 2 divisors, whose sum is σ = 101011100999490. Its totient is φ = 101011100999488.

The previous prime is 101011100999437. The next prime is 101011100999519. The reversal of 101011100999489 is 984999001110101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90001366479025 + 11009734520464 = 9486905^2 + 3318092^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101011100999489 is a prime.

It is a super-2 number, since 2×1010111009994892 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 101011100999489.

It is not a weakly prime, because it can be changed into another prime (101011100999989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50505550499744 + 50505550499745.

It is an arithmetic number, because the mean of its divisors is an integer number (50505550499745).

Almost surely, 2101011100999489 is an apocalyptic number.

It is an amenable number.

101011100999489 is a deficient number, since it is larger than the sum of its proper divisors (1).

101011100999489 is an equidigital number, since it uses as much as digits as its factorization.

101011100999489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 209952, while the sum is 53.

The spelling of 101011100999489 in words is "one hundred one trillion, eleven billion, one hundred million, nine hundred ninety-nine thousand, four hundred eighty-nine".