1010111011997 has 2 divisors, whose sum is σ = 1010111011998. Its totient is φ = 1010111011996.

The previous prime is 1010111011979. The next prime is 1010111012017. The reversal of 1010111011997 is 7991101110101.

Together with previous prime (1010111011979) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 537456136996 + 472654875001 = 733114^2 + 687499^2 .

It is a cyclic number.

It is not a de Polignac number, because 1010111011997 - 2¹⁴ = 1010110995613 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010111011697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505055505998 + 505055505999.

It is an arithmetic number, because the mean of its divisors is an integer number (505055505999).

Almost surely, 2^{1010111011997} is an apocalyptic number.

It is an amenable number.

1010111011997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010111011997 is an equidigital number, since it uses as much as digits as its factorization.

1010111011997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 567, while the sum is 32.

The spelling of 1010111011997 in words is "one trillion, ten billion, one hundred eleven million, eleven thousand, nine hundred ninety-seven".