Base | Representation |
---|---|
bin | 11101011001011110111… |
… | …00100001100100000111 |
3 | 10120120021112102101002202 |
4 | 32230233130201210013 |
5 | 113022203002234343 |
6 | 2052012322025115 |
7 | 132656356364366 |
oct | 16545734414407 |
9 | 3516245371082 |
10 | 1010113321223 |
11 | 35a4286aa906 |
12 | 143924aa819b |
13 | 7433a5b1c96 |
14 | 36c656677dd |
15 | 1b41e55adb8 |
hex | eb2f721907 |
1010113321223 has 2 divisors, whose sum is σ = 1010113321224. Its totient is φ = 1010113321222.
The previous prime is 1010113321219. The next prime is 1010113321241. The reversal of 1010113321223 is 3221233110101.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1010113321223 - 22 = 1010113321219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1010113321195 and 1010113321204.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1010113321823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505056660611 + 505056660612.
It is an arithmetic number, because the mean of its divisors is an integer number (505056660612).
Almost surely, 21010113321223 is an apocalyptic number.
1010113321223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010113321223 is an equidigital number, since it uses as much as digits as its factorization.
1010113321223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 1010113321223 its reverse (3221233110101), we get a palindrome (4231346431324).
The spelling of 1010113321223 in words is "one trillion, ten billion, one hundred thirteen million, three hundred twenty-one thousand, two hundred twenty-three".
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