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1010141444131 is a prime number
BaseRepresentation
bin11101011001100010001…
…11110011100000100011
310120120100111100011110221
432230301013303200203
5113022232202203011
62052015204503511
7132660150414361
oct16546107634043
93516314304427
101010141444131
1135a442568a86
121439323aab97
137434337a761
1436c692a8631
151b421c63971
hexeb311f3823

1010141444131 has 2 divisors, whose sum is σ = 1010141444132. Its totient is φ = 1010141444130.

The previous prime is 1010141444119. The next prime is 1010141444177. The reversal of 1010141444131 is 1314441410101.

It is a happy number.

1010141444131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1010141444131 - 235 = 975781705763 is a prime.

It is a super-2 number, since 2×10101414441312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1010141444096 and 1010141444105.

It is not a weakly prime, because it can be changed into another prime (1010141444111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505070722065 + 505070722066.

It is an arithmetic number, because the mean of its divisors is an integer number (505070722066).

Almost surely, 21010141444131 is an apocalyptic number.

1010141444131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010141444131 is an equidigital number, since it uses as much as digits as its factorization.

1010141444131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 1010141444131 its reverse (1314441410101), we get a palindrome (2324582854232).

The spelling of 1010141444131 in words is "one trillion, ten billion, one hundred forty-one million, four hundred forty-four thousand, one hundred thirty-one".