Base | Representation |
---|---|
bin | 101111000010101000… |
… | …0101101111100110011 |
3 | 100122202020221201021101 |
4 | 1132011100231330303 |
5 | 3123342110000201 |
6 | 114224041105231 |
7 | 10204240555405 |
oct | 1360520557463 |
9 | 318666851241 |
10 | 101020000051 |
11 | 3992a17a253 |
12 | 176b3488217 |
13 | 96abc30079 |
14 | 4c646d6b75 |
15 | 2963a6bd01 |
hex | 178542df33 |
101020000051 has 2 divisors, whose sum is σ = 101020000052. Its totient is φ = 101020000050.
The previous prime is 101019999991. The next prime is 101020000063. The reversal of 101020000051 is 150000020101.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (150000020101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101020000051 - 27 = 101019999923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 101019999992 and 101020000037.
It is not a weakly prime, because it can be changed into another prime (101020000351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50510000025 + 50510000026.
It is an arithmetic number, because the mean of its divisors is an integer number (50510000026).
Almost surely, 2101020000051 is an apocalyptic number.
101020000051 is a deficient number, since it is larger than the sum of its proper divisors (1).
101020000051 is an equidigital number, since it uses as much as digits as its factorization.
101020000051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10, while the sum is 10.
Adding to 101020000051 its reverse (150000020101), we get a palindrome (251020020152).
The spelling of 101020000051 in words is "one hundred one billion, twenty million, fifty-one", and thus it is an aban number.
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