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101021112013 is a prime number
BaseRepresentation
bin101111000010101010…
…0111101011011001101
3100122202100001012121011
41132011110331123031
53123342401041023
6114224121005221
710204253166313
oct1360524753315
9318670035534
10101021112013
113992a869728
12176b3923811
1396ac22c233
144c649060b3
152963bdb50d
hex178553d6cd

101021112013 has 2 divisors, whose sum is σ = 101021112014. Its totient is φ = 101021112012.

The previous prime is 101021111981. The next prime is 101021112047. The reversal of 101021112013 is 310211120101.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88100925124 + 12920186889 = 296818^2 + 113667^2 .

It is a cyclic number.

It is not a de Polignac number, because 101021112013 - 25 = 101021111981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 101021111984 and 101021112002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101021113013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50510556006 + 50510556007.

It is an arithmetic number, because the mean of its divisors is an integer number (50510556007).

Almost surely, 2101021112013 is an apocalyptic number.

It is an amenable number.

101021112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

101021112013 is an equidigital number, since it uses as much as digits as its factorization.

101021112013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 101021112013 its reverse (310211120101), we get a palindrome (411232232114).

The spelling of 101021112013 in words is "one hundred one billion, twenty-one million, one hundred twelve thousand, thirteen".