10102130021 has 2 divisors, whose sum is σ = 10102130022. Its totient is φ = 10102130020.

The previous prime is 10102130009. The next prime is 10102130023. The reversal of 10102130021 is 12003120101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6595713796 + 3506416225 = 81214^2 + 59215^2 .

It is a cyclic number.

It is not a de Polignac number, because 10102130021 - 2⁶ = 10102129957 is a prime.

It is a super-2 number, since 2×10102130021² (a number of 21 digits) contains 22 as substring.

Together with 10102130023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10102129984 and 10102130011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10102130023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5051065010 + 5051065011.

It is an arithmetic number, because the mean of its divisors is an integer number (5051065011).

Almost surely, 2^10102130021 is an apocalyptic number.

It is an amenable number.

10102130021 is a deficient number, since it is larger than the sum of its proper divisors (1).

10102130021 is an equidigital number, since it uses as much as digits as its factorization.

10102130021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 10102130021 its reverse (12003120101), we get a palindrome (22105250122).

The spelling of 10102130021 in words is "ten billion, one hundred two million, one hundred thirty thousand, twenty-one".