Search a number
-
+
1010441213134 = 22334576354097
BaseRepresentation
bin11101011010000101111…
…11010101010011001110
310120121010101102000020121
432231002333111103032
5113023340422310014
62052105033535154
7133000450412443
oct16550277252316
93517111360217
101010441213134
1135a5867a4961
121439b68744ba
13743904c7372
1436c9701b9ca
151b43d229124
hexeb42fd54ce

1010441213134 has 16 divisors (see below), whose sum is σ = 1582017903648. Its totient is φ = 483114627072.

The previous prime is 1010441213129. The next prime is 1010441213143. The reversal of 1010441213134 is 4313121440101.

It is a super-2 number, since 2×10104412131342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1010441213099 and 1010441213108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3018027 + ... + 3336070.

It is an arithmetic number, because the mean of its divisors is an integer number (98876118978).

Almost surely, 21010441213134 is an apocalyptic number.

1010441213134 is a deficient number, since it is larger than the sum of its proper divisors (571576690514).

1010441213134 is a wasteful number, since it uses less digits than its factorization.

1010441213134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6357579.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1010441213134 its reverse (4313121440101), we get a palindrome (5323562653235).

The spelling of 1010441213134 in words is "one trillion, ten billion, four hundred forty-one million, two hundred thirteen thousand, one hundred thirty-four".

Divisors: 1 2 23 46 3457 6914 79511 159022 6354097 12708194 146144231 292288462 21966113329 43932226658 505220606567 1010441213134