Base | Representation |
---|---|
bin | 11101011010000101111… |
… | …11010101010011001110 |
3 | 10120121010101102000020121 |
4 | 32231002333111103032 |
5 | 113023340422310014 |
6 | 2052105033535154 |
7 | 133000450412443 |
oct | 16550277252316 |
9 | 3517111360217 |
10 | 1010441213134 |
11 | 35a5867a4961 |
12 | 1439b68744ba |
13 | 743904c7372 |
14 | 36c9701b9ca |
15 | 1b43d229124 |
hex | eb42fd54ce |
1010441213134 has 16 divisors (see below), whose sum is σ = 1582017903648. Its totient is φ = 483114627072.
The previous prime is 1010441213129. The next prime is 1010441213143. The reversal of 1010441213134 is 4313121440101.
It is a super-2 number, since 2×10104412131342 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1010441213099 and 1010441213108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3018027 + ... + 3336070.
It is an arithmetic number, because the mean of its divisors is an integer number (98876118978).
Almost surely, 21010441213134 is an apocalyptic number.
1010441213134 is a deficient number, since it is larger than the sum of its proper divisors (571576690514).
1010441213134 is a wasteful number, since it uses less digits than its factorization.
1010441213134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6357579.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1010441213134 its reverse (4313121440101), we get a palindrome (5323562653235).
The spelling of 1010441213134 in words is "one trillion, ten billion, four hundred forty-one million, two hundred thirteen thousand, one hundred thirty-four".
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