1010441213143 has 2 divisors, whose sum is σ = 1010441213144. Its totient is φ = 1010441213142.

The previous prime is 1010441213129. The next prime is 1010441213153. The reversal of 1010441213143 is 3413121440101.

It is a strong prime.

It is an emirp because it is prime and its reverse (3413121440101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1010441213143 - 2¹⁷ = 1010441082071 is a prime.

It is a super-3 number, since 3×1010441213143³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1010441213153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505220606571 + 505220606572.

It is an arithmetic number, because the mean of its divisors is an integer number (505220606572).

Almost surely, 2^{1010441213143} is an apocalyptic number.

1010441213143 is a deficient number, since it is larger than the sum of its proper divisors (1).

1010441213143 is an equidigital number, since it uses as much as digits as its factorization.

1010441213143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1010441213143 its reverse (3413121440101), we get a palindrome (4423562653244).

The spelling of 1010441213143 in words is "one trillion, ten billion, four hundred forty-one million, two hundred thirteen thousand, one hundred forty-three".