Base | Representation |
---|---|
bin | 11101011010000101111… |
… | …11110010001011001111 |
3 | 10120121010101122000111002 |
4 | 32231002333302023033 |
5 | 113023340440101112 |
6 | 2052105040250515 |
7 | 133000451414324 |
oct | 16550277621317 |
9 | 3517111560432 |
10 | 1010441331407 |
11 | 35a586875802 |
12 | 1439b6910a3b |
13 | 74390539151 |
14 | 36c9704cb4b |
15 | 1b43d24e1c2 |
hex | eb42ff22cf |
1010441331407 has 2 divisors, whose sum is σ = 1010441331408. Its totient is φ = 1010441331406.
The previous prime is 1010441331353. The next prime is 1010441331437. The reversal of 1010441331407 is 7041331440101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1010441331407 - 234 = 993261462223 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1010441331407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1010441331437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505220665703 + 505220665704.
It is an arithmetic number, because the mean of its divisors is an integer number (505220665704).
Almost surely, 21010441331407 is an apocalyptic number.
1010441331407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010441331407 is an equidigital number, since it uses as much as digits as its factorization.
1010441331407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4032, while the sum is 29.
Adding to 1010441331407 its reverse (7041331440101), we get a palindrome (8051772771508).
The spelling of 1010441331407 in words is "one trillion, ten billion, four hundred forty-one million, three hundred thirty-one thousand, four hundred seven".
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