Base | Representation |
---|---|
bin | 11101011010000101111… |
… | …11110010001010011001 |
3 | 10120121010101122000102002 |
4 | 32231002333302022121 |
5 | 113023340440100403 |
6 | 2052105040250345 |
7 | 133000451414216 |
oct | 16550277621231 |
9 | 3517111560362 |
10 | 1010441331353 |
11 | 35a586875763 |
12 | 1439b69109b5 |
13 | 7439053910c |
14 | 36c9704cb0d |
15 | 1b43d24e188 |
hex | eb42ff2299 |
1010441331353 has 2 divisors, whose sum is σ = 1010441331354. Its totient is φ = 1010441331352.
The previous prime is 1010441331241. The next prime is 1010441331407. The reversal of 1010441331353 is 3531331440101.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 728271078544 + 282170252809 = 853388^2 + 531197^2 .
It is a cyclic number.
It is not a de Polignac number, because 1010441331353 - 210 = 1010441330329 is a prime.
It is not a weakly prime, because it can be changed into another prime (1010441361353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505220665676 + 505220665677.
It is an arithmetic number, because the mean of its divisors is an integer number (505220665677).
Almost surely, 21010441331353 is an apocalyptic number.
It is an amenable number.
1010441331353 is a deficient number, since it is larger than the sum of its proper divisors (1).
1010441331353 is an equidigital number, since it uses as much as digits as its factorization.
1010441331353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6480, while the sum is 29.
Adding to 1010441331353 its reverse (3531331440101), we get a palindrome (4541772771454).
The spelling of 1010441331353 in words is "one trillion, ten billion, four hundred forty-one million, three hundred thirty-one thousand, three hundred fifty-three".
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