101050650331 has 2 divisors, whose sum is σ = 101050650332. Its totient is φ = 101050650330.

The previous prime is 101050650329. The next prime is 101050650361. The reversal of 101050650331 is 133056050101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101050650331 - 2¹ = 101050650329 is a prime.

It is a super-2 number, since 2×101050650331² (a number of 23 digits) contains 22 as substring.

Together with 101050650329, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 101050650296 and 101050650305.

It is not a weakly prime, because it can be changed into another prime (101050650361) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50525325165 + 50525325166.

It is an arithmetic number, because the mean of its divisors is an integer number (50525325166).

Almost surely, 2^101050650331 is an apocalyptic number.

101050650331 is a deficient number, since it is larger than the sum of its proper divisors (1).

101050650331 is an equidigital number, since it uses as much as digits as its factorization.

101050650331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1350, while the sum is 25.

The spelling of 101050650331 in words is "one hundred one billion, fifty million, six hundred fifty thousand, three hundred thirty-one".