1011000013032 has 32 divisors (see below), whose sum is σ = 2575188715680. Its totient is φ = 330641513280.

The previous prime is 1011000012973. The next prime is 1011000013039. The reversal of 1011000013032 is 2303100001101.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a junction number, because it is equal to n+sod(n) for n = 1011000012999 and 1011000013017.

It is not an unprimeable number, because it can be changed into a prime (1011000013039) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397404394 + ... + 397406937.

It is an arithmetic number, because the mean of its divisors is an integer number (80474647365).

Almost surely, 2^{1011000013032} is an apocalyptic number.

1011000013032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1011000013032 is an abundant number, since it is smaller than the sum of its proper divisors (1564188702648).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1011000013032 is a wasteful number, since it uses less digits than its factorization.

1011000013032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 794811393 (or 794811389 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 1011000013032 its reverse (2303100001101), we get a palindrome (3314100014133).

The spelling of 1011000013032 in words is "one trillion, eleven billion, thirteen thousand, thirty-two".