Base | Representation |
---|---|
bin | 10110111111001100110011… |
… | …100011011100011100111111 |
3 | 111020222002000210202102022112 |
4 | 112333030303203130130333 |
5 | 101222411001112011033 |
6 | 555004424514004235 |
7 | 30203145504611141 |
oct | 2677146343343477 |
9 | 436862023672275 |
10 | 101100100110143 |
11 | 2a239347924422 |
12 | b409a62b7667b |
13 | 44549108a2b94 |
14 | 1ad73b16d8c91 |
15 | ba4ca3e47c48 |
hex | 5bf3338dc73f |
101100100110143 has 2 divisors, whose sum is σ = 101100100110144. Its totient is φ = 101100100110142.
The previous prime is 101100100110073. The next prime is 101100100110161. The reversal of 101100100110143 is 341011001001101.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101100100110143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (101100100110193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550050055071 + 50550050055072.
It is an arithmetic number, because the mean of its divisors is an integer number (50550050055072).
Almost surely, 2101100100110143 is an apocalyptic number.
101100100110143 is a deficient number, since it is larger than the sum of its proper divisors (1).
101100100110143 is an equidigital number, since it uses as much as digits as its factorization.
101100100110143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 14.
Adding to 101100100110143 its reverse (341011001001101), we get a palindrome (442111101111244).
The spelling of 101100100110143 in words is "one hundred one trillion, one hundred billion, one hundred million, one hundred ten thousand, one hundred forty-three".
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