10110010211117 has 2 divisors, whose sum is σ = 10110010211118. Its totient is φ = 10110010211116.

The previous prime is 10110010211111. The next prime is 10110010211123. The reversal of 10110010211117 is 71111201001101.

It is a balanced prime because it is at equal distance from previous prime (10110010211111) and next prime (10110010211123).

It can be written as a sum of positive squares in only one way, i.e., 9185439501001 + 924570710116 = 3030749^2 + 961546^2 .

It is a cyclic number.

It is not a de Polignac number, because 10110010211117 - 2⁶ = 10110010211053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10110010211095 and 10110010211104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10110010211111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5055005105558 + 5055005105559.

It is an arithmetic number, because the mean of its divisors is an integer number (5055005105559).

Almost surely, 2^{10110010211117} is an apocalyptic number.

It is an amenable number.

10110010211117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10110010211117 is an equidigital number, since it uses as much as digits as its factorization.

10110010211117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 17.

Adding to 10110010211117 its reverse (71111201001101), we get a palindrome (81221211212218).

The spelling of 10110010211117 in words is "ten trillion, one hundred ten billion, ten million, two hundred eleven thousand, one hundred seventeen".