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101100552019 is a prime number
BaseRepresentation
bin101111000101000001…
…1111111111101010011
3100122221212112011210121
41132022003333331103
53124023220131034
6114240035411111
710206236340655
oct1361203777523
9318855464717
10101100552019
1139970698125
1217716453a97
1396c282475c
144c712a46d5
15296ab7e1b4
hex178a0fff53

101100552019 has 2 divisors, whose sum is σ = 101100552020. Its totient is φ = 101100552018.

The previous prime is 101100551963. The next prime is 101100552023. The reversal of 101100552019 is 910255001101.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101100552019 - 29 = 101100551507 is a prime.

It is a super-2 number, since 2×1011005520192 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101100551984 and 101100552002.

It is not a weakly prime, because it can be changed into another prime (101100552079) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50550276009 + 50550276010.

It is an arithmetic number, because the mean of its divisors is an integer number (50550276010).

Almost surely, 2101100552019 is an apocalyptic number.

101100552019 is a deficient number, since it is larger than the sum of its proper divisors (1).

101100552019 is an equidigital number, since it uses as much as digits as its factorization.

101100552019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 25.

The spelling of 101100552019 in words is "one hundred one billion, one hundred million, five hundred fifty-two thousand, nineteen".