1011011000141 has 2 divisors, whose sum is σ = 1011011000142. Its totient is φ = 1011011000140.

The previous prime is 1011011000123. The next prime is 1011011000147. The reversal of 1011011000141 is 1410001101101.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1007925642025 + 3085358116 = 1003955^2 + 55546^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1011011000141 is a prime.

It is a super-2 number, since 2×1011011000141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1011011000147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 505505500070 + 505505500071.

It is an arithmetic number, because the mean of its divisors is an integer number (505505500071).

Almost surely, 2^{1011011000141} is an apocalyptic number.

It is an amenable number.

1011011000141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1011011000141 is an equidigital number, since it uses as much as digits as its factorization.

1011011000141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 1011011000141 its reverse (1410001101101), we get a palindrome (2421012101242).

The spelling of 1011011000141 in words is "one trillion, eleven billion, eleven million, one hundred forty-one", and thus it is an aban number.